Problem Statement
Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:
Input: x = 123 Output: 321
Example 2:
Input: x = -123 Output: -321
Example 3:
Input: x = 120 Output: 21
Constraints:
-231 <= x <= 231 - 1
Solution Program
[C++]
class Solution {
public:
int reverse(int x) {
int ans = 0;
while(x!=0){
int digit=x%10;
if((ans>INT_MAX/10) || (ans<INT_MIN/10)){
return 0;
}
ans=(ans*10)+digit;
x=x/10;
}
return ans;
}
};
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